(x+2)(x+3)=(x^2+5x+6

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Solution for (x+2)(x+3)=(x^2+5x+6 equation: 



(x+2)(x+3)=(x^2+5x+6

We move all terms to the left:

(x+2)(x+3)-((x^2+5x+6)=0

We multiply parentheses ..

(+x^2+3x+2x+6)-((x^2+5x+6)=0



We calculate terms in parentheses: -((x^2+5x+6), so:

(x^2+5x+6



We get rid of parentheses

x^2+3x+2x-((x^2+5x+6)+6=0

We add all the numbers together, and all the variables

x^2+5x-((x^2+5x+6)+6=0

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